Mark, I think there might be an error here.
Have you calculated the centre of area correctly for each of the junk sails? doesn't look quite right. In each case, the centre of area should be on a vertical line which goes through the midpoint of the boom. (That's the quick and easy way we do it for junk sails). It doesn't matter about where it is on the sail, up or down, all that matters is the position of that vertical line. The fore-sail centre looks incorrect to me.
I have marked the two lines (A and B) where they should be on your diagram ( but only roughly, I am eye-balling off the screen, just to show you the idea, You will need to check the accuracy.

Now, the next thing you must do is calculate the resultant of these two centres. It looks to me as though you have just chosen the midpoint of the two, but that would be incorrect. The position on a line between the two centres is not the mid point, but a point which takes into account, in a proportional way, the AREA of each of the two sails.
I don't know the two areas - the fore sail is smaller in area than the aft sail, I can see that, so straight away I know that the combined centre will not be at the midpoint of the two component vertical lines.
Here's how you do it. Let us say the aft sail is 120 sq m and the fore sail is 80 sq m (just to give a simple example, with simple numbers.) Add the two areas together and we get a total of 200 sq m. The aft sail is thus 120/200 = 3/5 of the total area. And the fore sail is thus 80/200 = 2/5 of the total area.
Suppose the distance between those two vertical lines (representing the two centres) is 4.5m, just to use an easy number. Then the resultant centre will need to be at a point which divides the 4.5m into proportions 3/5 and 2/5 (not half way). It will be biased towards the larger of the two areas, so it will be 2/5 of the distance from the aft centre.
(ie 3/5 x 4.5 = 2.7)
and, just to check, 3/5 of the distance from the fore centre.
(ie 2/5 x 4.5 = 1.8)
So, the resultant line divides the 4.5 into 2.7 and 1.8 - not half way.

Note, I assume you have the area of the mains'l and genoa of the original rig, and have found their geometric centres correctly. It looks as though you have. But again, unless the two sails happen to have equal areas, the resultant CoE will not be midway between them, but in a position proportional to their respective areas with the bias towards the larger of the two sails, same as above. Check you have done that correctly then do your superposition of the junk rig as above.
Forgive me if you already know all that, but it does look a bit as though your diagram might have been incorrect.